4x^4-4x^3-3x^2+4x-1

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4x^4-4x^3-3x^2+4x-14x^4-4x^3-3x^2+4x-14x^4-4x^3-3x^2+4x-14x^4-4x^3-3x^2+4x-14x^4-4x^3-3x^2+4x-1=(4x^

4x^4-4x^3-3x^2+4x-1
4x^4-4x^3-3x^2+4x-1

4x^4-4x^3-3x^2+4x-1
4x^4-4x^3-3x^2+4x-1

4x^4-4x^3-3x^2+4x-1=(4x^2-4x+1)(x^2-1)=(x+1)(x-1)(2x-1)^2<0,所以-1

4x^4-4x^3-3x^2+4x-1<0
4x^3(x-1)-(3x-1)(x-1)<0
(x-1)(4x^3-3x+1)<0
可知x<-1

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