若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2
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若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2若x\y=2\7,求7x^2-3xy+2y^2\2x
若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2
若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2
若x\y=2\7,求7x^2-3xy+2y^2\2x^2-3xy+7y^2
中间除号两边的多项式因该都带括号吧,否则此题不能求出具体的数解.
即(7x^2-3xy+2y^2)/(2x^2-3xy+7y^2)
将分子分母同除以y^2
得 (7x^2/y^2-3x/y+2)/(2x^2/y^2-3x/y+7)
即(7*4/49-3*2/7+2)/(2*4/49-3*2/7+7)
=(4/7-6/7+2)/(8/49-6/7+7)
=(12/7)/(309/49)
=28/103
(7x^2-3xy+2y^2)\(2x^2-3xy+7y^2) 上下同除y^2得到
=[7(x/y)^2-3(x/y)+2]\[2(x/y)^2-3(x/y)+7] 代入x\y=2\7得到
=[7(4/49)-3(2/7)+2]\[2(4/49)-3(2/7)+7]
=(4/7-6/7+14/7)/(8/49-42/49+343/49)
=(12/7)/(309/49)
=(12*49)/(7*309)
=28/103
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