求证sin(a+b)sin(a-b)=sina^2-cosb^2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/28 02:36:39
求证sin(a+b)sin(a-b)=sina^2-cosb^2求证sin(a+b)sin(a-b)=sina^2-cosb^2求证sin(a+b)sin(a-b)=sina^2-cosb^2证明:s
求证sin(a+b)sin(a-b)=sina^2-cosb^2
求证sin(a+b)sin(a-b)=sina^2-cosb^2
求证sin(a+b)sin(a-b)=sina^2-cosb^2
证明:sin(a+b)sin(a-b)
=(sinacosb+cosasinb)(sinacosb-cosasinb)
=(sinacosb)^2-(cosasinb)^2
=(cosb)^2[1-(cosa)^2]-(cosa)^2[1-(cosb)^2]
=(cosb)^2-(cosb)^2(cosa)^2-(cosa)^2+(cosa)^2(cosb)^2
=(cosb)^2-(cosa)^2
=(cosb)^2-[1-(sina)^2]
=(sina)^2+(cosb)^2-1
=(sina)^2-(sinb)^2
题目有问题,请楼主认真核对!
sin(a+b)sin(a-b)=(-1/2)(cos2a-cos2b)
=(-1/2)(1-2sin²a+2cos²b-1)
=sin²a-cos²b
求证恒等式sin(A+B)sin(A-B)=sin²A-sin²B
求证:sin(a+b)sin(a-b)=sin^2a-sin^2b
sin(a+b)sin(a-b)=sin2a-sin2b求证
求证:sin(A+B)sin(A-B)=sinAsinA-sinBsinB
3 在三角形ABC中,已知(a2+b2)sin(A-B)=(a2-b2)sin(A+B) 求证:ABC是等腰或直角三角形(a^2+b^2)sin(A-B)=(a^2-b^2)sin(A+B),(sin^A+sin^B)sin(A-B)=(sin^A-sin^B)sin(A+B) sin^A*(sin(A+B)-sin(A-B))=sin^B*(sin(A-B)+sin(A+B)) sin^A*2c
求证(a^2+b^2-c^2)/(b^2+c^2-a^2)=(sin(A+B)+sin(A-B))/(sin(A+B)-sin(A-B))
设A,B为锐角,且sin^2A+sin^B=sin(A+B),求证A+B=90sin^2A+sin^2B=sin(A+B)sin^2A表示sinA的平方
在△ABC中,求证;sin^(A/2)+sin^(B/2)+sin^(C/2)=1-2sin(A/2)sin(B/2)sin(C/2)
已知3sin b=sin(2a+b) 求证tan(a+b)=2tana
已知 3sin A = sin (2B +A ),求证 : tan(A+B)= 2tanB
sin^2A+sin^2B=sin^2C求证△ABC的形状
求证恒等式sin(a十b)sin(a一b)=sina2一sinb2
求证cos2a-cos2b=-2sin(a+b)sin(a-b)
1/2(cos2A-cos2B)=sin(A+B)sin(A-B)求证
求证sin(a+b)sin(a-b)=sina^2-cosb^2
求证:sin(a+b)cosa-(1/2)[sin(2a+b)-sinb]=sinb
求证cosa*sinb=1/2[sin(a+b)-sin(a-b)]
证明sin(a+b)sin(a-b)=sin^2 a-sin^2 b,