(x+y)²-10(x+y)+25

(x+y)²-10(x+y)+25 已知x²y²+x²+y²=10xy-16 求x,y x²-y²-x-y因式分解 x²+y²-2x-6y+10=0 求分式x²-y²/xy 若x²+y²+4x-10y+29=0,则x²y+xy²= ( x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0 )求出x,y 49+14x+x²-y² 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y 已知x²-4x+y²-10y+29=0.求x²y²+2x³y²+[x²]²y²的值. 分解因式 x²-4x+y-10y+29 [(x-y)²+(x+y)(x-y)]除以2x （x+y)²-4(x+y-1) （x+y)²-10(x+y)+25 4m²-9n²-4m+1 因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT （x+y）²-2(x²-y²)+（y-x）² 9(x-y)²+12(x²-y²)+4(x+y)² 因式分解 已知(x+y)²;=8,(x-y)²;=4,求x²+y² 分解公因式 （x+y）²-2（x²-y²）+（x-y）²