f(x)二阶可导,g(x) =∫(0,1)f(xt)dt,且lim x→0 f(x)/x =A问g'(x)在x=0处是否连续

max{f(x),g(x)}=1/2(f(x)+g(x)+|f(x)-g(x)| 陈文灯《复习指南》中定积分一道计算题·设函数f(x),g(x) 满足f'(x)=g(x),g'(x)=2e^x-f(x),且f(0)=0,g(0)=2.求∫[g(x)/(1+x)-f(x)/(1+x^2)] dx (定积分上下限分别为π,0)由f'(x)=g(x),g'(x)=2e^x-f(x),得f''(x)=2e^x-f(x),于是 已知f'(x)=g(x),g'(x)=f(x),f(0)=1,g(0)=0,证f^2(x)+g^2(x)=1 设f(x)=x g(x)=2x-1 则f(g(0))= 设f(x)连续,g(x) =∫(1,0)f(xt)dt,且lim x→0 f(x)/x =A,求 g'(x).如题 f(x)二阶可导,g(x) =∫(0,1)f(xt)dt,且lim x→0 f(x)/x =A问g'(x)在x=0处是否连续 f(x)=2x-1,g(x)=x^2,则f[g(x)]=?,g[f(x)]=?,f[f(x)]=?,g[g(x)]=? f（x）=x²-1,g（x）=x-1＞0,x＞0 2-x＜0,x＜0,求f[g(2)] g[f(2)],f[g(x)],g[f(x)] 高等代数(x^2+1)h(x)+(x-1)f(x)+(x+2)g(x)=0(x^2+1)h(x)+(x+1)f(x)+(x-2)g(x)=0证明h(x)|(f(x),g(x)) 已知f(x)=x^2-1,g(x)=x-1(x小于0)或2-x(x大于0),求f[g(x)]与[f(x)] 高数 ：f(x+y)=f(x)g(y)+f(y)g(x),f'(0)=g(0)=1,f(0)=g'(0)=0证明f(x)在R上可导且f'(x)=g(x) 函数f(x),g(x)满足f(x)=f(-x),g(-x)=-g(x),且g(x)=f(x-1),若f(0)=2015,则f(2012)=多少 在R[x]中,定义内积(f(x),g(x))=∫（0,1）f(x)g(x)dx,则f(x)=1,g（x）=x的夹角是多少? 已知f(x),g(x)都为偶函数,当x>0时,f'(x)g(x)-f(x)g'(x)<0,且f(2)=0.求f(x+1)/g(x+1)的解集 f(x)和g(x)分别是一个奇函数和偶函数,若f(x)-g(x)=(0.5)^x,则f(1),g(0),g(-2)的大小 f(x)=x2-1 g(x)=x-1 x>0 g(x)=2-x x f(x)=x2-1,g(x)=x-1(x>0) g(x)=2-x(x 设f(x)是连续函数,且lim(x>0)f(x)/x=2,若g(x)=∫(0到1)f(xt)dt,试求g'(x),并讨论g'(x)在x=0处的连续性设f(x)是连续函数,且lim(x>0)f(x)/x=2,若g(x)=∫（0到1）f(xt)dt,试求g'(x),并讨论g'(x)在x=0处的连续性