a^m+1b^n+a^mb^n+1因式分解

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a^m+1b^n+a^mb^n+1因式分解a^m+1b^n+a^mb^n+1因式分解a^m+1b^n+a^mb^n+1因式分解a^m+1b^n+a^mb^n+1=a^m(1+b^n)+(b^n+1)=

a^m+1b^n+a^mb^n+1因式分解
a^m+1b^n+a^mb^n+1因式分解

a^m+1b^n+a^mb^n+1因式分解
a^m+1b^n+a^mb^n+1=a^m(1+b^n)+(b^n+1)
=(a^m+1)(b^n+1)

a^(m+1)b^n + a^mb^(n+1)
=(a^m)·(b^n)·(a+b)