1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
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1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5
1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
1.已知m^2-5m-1=0,求(m^4+1)/m^2的值
2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值
3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
第三题:对右边 分母化为 x-2 x-5的乘积,化解 与左边对应,相同次数的系数相等
没带纸笔
1q
MA=-2+5M+1
MA=5M-1
=<(5M-1)4+1>/(5M-1)2
=20M-4+1/10M-2
=20M-3/IOM-2
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m*m-5m-1=0则2m*m-5m+1/m*m