f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?
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f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?f(x)=根号2sin(2x-π/4),
f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?
f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?
f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值?
因为x∈[π/8,3π/4],所以2x-π/4∈[0,5π/4]
显然,当2x-π/4=π/2,即x=3π/8时,函数取最大值,为√2.
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