(x+1)(y+1)(x-1)(y-1)化简.
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(x+1)(y+1)(x-1)(y-1)化简.(x+1)(y+1)(x-1)(y-1)化简.(x+1)(y+1)(x-1)(y-1)化简.=[(x+1)(x-1)][(y+1)(y-1)]=(x
(x+1)(y+1)(x-1)(y-1)化简.
(x+1)(y+1)(x-1)(y-1)化简.
(x+1)(y+1)(x-1)(y-1)化简.
=[(x+1)(x-1)][(y+1)(y-1)]
=(x²-1)(y²-1)
=x²y²-x²-y²+1
(x+1)(y+1)(x-1)(y-1)
=(x²-1)(y²-1)
=x²y²-x²-y²+1
(x+y)(x-y)+4(y-1)
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
y'/y=1/x
计算：(1+ y/x-y )·(1- x/x+y)
感激不尽1.x,y满足(x-y-1)(x+y)
(1-y+x/y)除以y平方-x平方/x
证明:(y/x)+(x/y)+xy≥x+y+1
x+y分之1-(x+y)的平方x-y
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
1/(x-y)/(1/y-/x)
因式分解：（1+x+y)(1-x-y)
(x+5y)(x-7y-1)
（x+y)²-4(x+y-1)
(x-y)(2x-y-1)
（x+y)(x+y-1)-12因式分解
因式分解:(x+y)-4(x+y-1)
y'-(1/x)y=xe^-x
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简