(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
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(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
(4m+2)(2m+4)=[2*(2m+1)]*[2*(m+2)]=4(2m+n)(m+2n)
这种问题的通法是先展开 后重新因式分解
(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
4(m+n)^2-9(m-n)^2化成公因式
4m(m-m)-2n(n-m)
2x-4x-1化成(x+m)=n的形式 m= n=
(n/m+n/2m^2)*4m/n^2
因式分解4m^2(m-n)+4n(n-m)
4m(m-n)^2+4n(n-m)^3
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
4m^2(m+n)-9n^2(m+n)
(m-n)2(n-m)3(n-m)4化简
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
(m+n)^2+4m+4n+4m^2如何分解因式
(m-n)^2*(m-n)^4=?
化简,1.[(m+n-p)(m+p+n)-(m+n)²]/(-p),2.[(m+n)(m-n)-(m-n)²+2n(m-n)]/4n
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
m+n/4m^-n^-m-2m/n^-4m^=
(m-2n)(2n+m)-(-3m-4n)(4n-3m)=