25(3m–2n)∧2–9(m+4n)∧2 因式分解
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25(3m–2n)∧2–9(m+4n)∧2因式分解25(3m–2n)∧2–9(m+4n)∧2因式分解25(3m–2n)∧2–9(m+4n)∧2因式分解原式=[5(3m-2n)+3(m+4n)][5(3
25(3m–2n)∧2–9(m+4n)∧2 因式分解
25(3m–2n)∧2–9(m+4n)∧2 因式分解
25(3m–2n)∧2–9(m+4n)∧2 因式分解
原式=[5(3m-2n)+3(m+4n)][5(3m-2n)-3(m+4n)]=(18m+2n)(12m-22n)=4(9m+n)(6m-11n)
25(3m–2n)∧2–9(m+4n)∧2
25(3m–2n)∧2–9(m+4n)∧2 因式分解
4m^2(m+n)-9n^2(m+n)
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
4m(m-n)^2+4n(n-m)^3
(m-n)2(n-m)3(n-m)4化简
[(m+2n)(m-2n)-(m-2n)∧2]÷(-3n)∧2
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^
已知16∧m=4×2∧2n-2,27∧n=9×3∧m+3,求m,n的值
(m-2n)(2n+m)-(-3m-4n)(4n-3m)=
(3m-4n)(4n+3m)-(2m-n)(2m+n)
[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]
计算(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n),
若(m-2n)/(2m+n)=3,则[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)] - {9(m-2n)/[4(2m+n)]}的值是?