若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几
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若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几原方程变形为(X-4
若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几
若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几
若(X-4)^2+|X-2Y-6|=0,则X、Y的值分别为几
原方程变形为(X-4)^2=0 ① and |X-2Y-6|=0 ②,解方程①得X=4,代入②得Y=-1.∴原方程解为X=4 and Y=-1
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