设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/02 00:56:57
设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-
设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?
设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?
设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?
x^2+xy+y^2=0,两边除以y^2得,(x/y)^2+x/y+1=0,根据求根公式得,x/y=(-1+√3i)/2,或x/y=(-1-√3i)/2,当x/y=(-1+√3i)/2时,x/(x+y)=1-y/(x+y)=1-1/(x/y+1)=(1+√3i)/2,y/(x+y)=(1-√3i)/2,当x/y=(-1-√3i)/2时,x/(x+y)=(1-√3i)/2,y/(x+y)=(1+√3i)/2,两种情况都是[x/(x+y)]^2010-[y/(x+y)]^2010=[(1-√3i)/2]^2010+[(1+√3i)/2]^2010,计算[(1-√3i)/2]^3=-1,[(1+√3i)/2]^3=-1,所以原式=(-1)^670+(-1)^670=1+1=2
设非零复数x,y满足x^2+xy+y^2=0.则代数式[x/(x+y)]^2010-[y/(x+y)]^2010=?
设非零复数x,y满足x^2+xy+y^2=0,求代数式(x/x+y)^1990+(y/x+y)^1990的值
一道高中复数四则运算题目我不太懂,设非零复数x,y满足x^2+xy+y^2=0,则代数式[ x/(x+y)]^2010+[ y/(x+y)]^2010的值是多少?
已知实数xy满足x+2y
已知实数xy满足 x+y-2
正数x,y满足x-y=2xy,求x-y/x+y的值.
已知xy满足约束条件y=2 2X+y
已知x.y满足X2-y2=2xy.则x-y/x+y=?x.
若实数x,y满足x^2-xy-y^2 =0,则x/y=?
整数x,y满足方程2xy+x+y=83,则x+y怎么算
若正实数x.y满足x+y=xy,则x+2y的最小值
整数x,y满足x2-y2=2xy,求x-y/x+y的值
已知正整数x,y满足:xy-x-y=0,则x+2y的最小值
若正整数X,Y满足2X+Y--XY=0,求X+Y的最小值
正整数x,y满足x2-y2=2xy,求x-y/x+y的值
x,y满足2xy+x+y=83.x+y是何数?
已知正数x,y满足2x+8y-xy=0,x+y的最小值
若xy满足x²+2x+y-2√y-1=-1,求xy,