由X^2+Y^2+Z^2-2X+4Y+1/2=0配方得(X^2-2X+1)+(Y^2+4Y+4)+Z^2+1/2-1-4=0那配方数字1,4.是不是也可以用别的数!这道题要怎么解,下一步式子是什么?

1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z) 设f(x,y,z)=e^x*y*z^2,其中z=z(x,y)是由x+y=z+x*e^(z-x-y)确定的隐函数,则f'x(0,1,1)= 化简(x+Y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z) 计算题(x+y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z). 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) (x-y)^2+4z(x-y)+4z^2 分解因式 4a（x-y）²-a²（y-x）³ （x+y+z)（x-y+z）+(y-x+z) (y-x-z)（1）4a（x-y）²-a²（y-x）³ （2）（x+y+z)（x-y+z）+(y-x+z) (y-x-z) 计算:x^2/(x-y)(x-z)+y^2/(y-x)(y-z)+z^2/(z-x)(z-y) 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} 请问怎么由2x-3y+z=0 ,3x-2y-6z=0 得到x=3z,y=4z 设函数z=z(x,y)由方程x^2+y^3-xyz^1=0确定,求z/x,z/y x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z) 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答