若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=
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若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3
若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=
若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=
若(x^2+x+1)/x=4,则x^2/(3x^4-5x^2+3)=
x+1/x+1=4
x+1/x=3
(x+1/x)²=9,x²+1/x²=7
上下同除以x²得1/(3x²+3/x²-5)=1/(21-5)=1/16
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
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一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
若x+1/x=4,则x^2/(x^4+x^2+1)=
若1/x-x=3,则x^2/x^4+x^2+1=( )
若1/x+x=3,则x^2/x^4+x^2+1=____
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
(x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
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