AB=DC,AE=DF,CE=FB,求证AF=DE行了
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AB=DC,AE=DF,CE=FB,求证AF=DE行了AB=DC,AE=DF,CE=FB,求证AF=DE行了AB=DC,AE=DF,CE=FB,求证AF=DE行了∵AB=DC,∴AB+BC=DC+BC
AB=DC,AE=DF,CE=FB,求证AF=DE行了
AB=DC,AE=DF,CE=FB,求证AF=DE
行了
AB=DC,AE=DF,CE=FB,求证AF=DE行了
∵AB=DC,
∴AB+BC=DC+BC,即AC=DB
又有AE=DF,CE=BF
可得三角形ACE全等三角形DBF(SSS)
∴角CAE=角BDF
可得AE平行DF,而AE=DF
可得四边形AEDF为平行四边形
∴AF=DE
没图?
先画出图形 我们可以看到 AF=AB+BD+CD+CF DE=AB+BD+AE 又因为 AE=DF=CD+CF 所以 AF=DE
已知:如图,AB=DC,AE=DF,CE=FB,求证:AF=DE
已知如图AB=DC,AE=DF,CE=FB求证AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证:AF=DE
AB=DC,AE=DF,CE=FB,求证AF=DE行了
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