f(z）=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?z',z是复数!

f(z）=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?z',z是复数! （2）f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)（z=i）和Resf(z)（z=3i） f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)（z=i）和Resf(z)（z=3i） f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z) f(z)=2z+z的共轭-3i,f（z的共轭+i）=6-3i,试求f（-z） 已知f(z)=|1+z|-z(拔),又f(-z)=10+3i,求复数z已知f(z)=|1+z|-z(拔）,又f(-z)=10+3i,求复数z f(z)=2z+(共轭z)-3i,f(z0共轭+i)=6-3i,求f(-z0)注:共轭z表示z的共轭复数 已知f（z）=z^4+4z^3+8z^2+8z+5,则f（-1+2i）等于多少 已知f(z+i)=z+2z-2i,则f(i)=? 已知f（z）=1＋IzI-z,且f(-z)=10+3i,求复数z 若z的共轭复数为z f(z+i)=z+2i则 f(3+2i）= F(z)=|1+z|-z的共扼复数,且F(-z)=10-3i,求复数z 复变函数f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z) 复变函数f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z) 已知f(z)=2z+z^2+(1+i),则f(i)的值是 已知f(z)=2z+z²+(1+i)则f(i)的值是 已知f(z+i)=3z-2i,则f(i)= f(z）=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?我知道答案是-6-4i,大概过程我也明白,但没算明白,