(X) =x2-2x + 2a(a2-2ab-b2)-b(2a2 ab-b2)∴2ab/a b≤2ab/2√ab=√ab m<0,n<0,求(√-m)2 (√-n)2
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(X) =x2-2x + 2a(a2-2ab-b2)-b(2a2ab-b2)∴2ab/ab≤2ab/2√ab=√abm<0,n<0,求(√-m)2(√-n)2(X) =x2-2x + 2a(a2-2a
(X) =x2-2x + 2a(a2-2ab-b2)-b(2a2 ab-b2)∴2ab/a b≤2ab/2√ab=√ab m<0,n<0,求(√-m)2 (√-n)2
(X) =x2-2x + 2a(a2-2ab-b2)-b(2a2 ab-b2)
∴2ab/a b≤2ab/2√ab=√ab m<0,n<0,求(√-m)2 (√-n)2
(X) =x2-2x + 2a(a2-2ab-b2)-b(2a2 ab-b2)∴2ab/a b≤2ab/2√ab=√ab m<0,n<0,求(√-m)2 (√-n)2
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集合A={x|x2-ax+a2-19=0},B={x|x2-5x+6=0},C={x|x2+2x-8=0}.若集合A={x|x2-ax+a2-19=0},B={x|x2-5x+6=0},C={x|x2+2x-8=0}1)若A∩B=A∪B,求a的值
设关于x的不等式x2-(2a+1)x+a2+a-2>0和x2-(a2+a)x+a3
解方程:x2+ax-2a2=0.(a为已知常数)或(X+1)÷X2—2X2÷(X+1)=1解方程一:x2+ax-2a2=0.(a为已知常数)解方程二:(X+1)÷X2—2X2÷(X+1)=1
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1/x+1/x(x-1)=,(a2-a)除于a2-2a+1/a-1=,x-1/x-2除于x2-2x+1/x2-4=,
14.下列各因式分解中正确的是( ) A.a4-9a2+8=(a2-1)(a2-8) B.(3x2+5x)2+(3x2+5x)-6=(3x2+5x