已知π/6

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已知π/6已知π/6已知π/6sin(2π/3—a)=sin[π-(2π/3—a)]=sin(π/3+a)π/6n(2π/3—a)=sin[π-(2π/3—a)]=sin(π/3+a)π/6sin&s

已知π/6
已知π/6

已知π/6
sin(2π/3—a)=sin[π-(2π/3—a)]=sin(π/3+a)
π/6

n(2π/3—a)=sin[π-(2π/3—a)]=sin(π/3+a)
π/6sin²(π/3+a)＋cos²(a+π/3)=1
所以sin(π/3+a)=√(1-m²)
所以sin(2π/3 -a)=√(1-m²)

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