log2^x=log4^x,则x=
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log2^x=log4^x,则x=log2^x=log4^x,则x=log2^x=log4^x,则x=1设log2^x=log4^X=a则2^a=4^a=2^2a=x则a=2a则a=o则x=2^0=1
log2^x=log4^x,则x=
log2^x=log4^x,则x=
log2^x=log4^x,则x=
1
设log2^x=log4^X=a
则2^a=4^a=2^2a=x
则a=2a
则a=o
则x=2^0=1
确定是log不是lg?
log4(log2^x)=log2(log4^x)求log2^x
log2^x=log4^9
log2^x=log4^x,则x=
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