log2^x=log4^9
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log2^x=log4^9log2^x=log4^9log2^x=log4^9log2^x=log4^9=log2^2(3^2)=log2^3所以x=3asabovelog2^x=log4^9log2
log2^x=log4^9
log2^x=log4^9
log2^x=log4^9
log2^x=log4^9=log2^2 (3^2)=log2^3
所以x=3
as above
log2^x=log4^9
log2^x=log2^2*9
2^x=2^2*9
x=2*9=18
log2^x=log4^9
=>xlog2=9log2^2
=>xlog2=18log2
=>x=18
log2^x=log4^9
log4(log2^x)=log2(log4^x)求log2^x
log2(x-2)=log4(5-x)
log4 (x+2) - log2 (x-1) = 是不是要把log4 转换成log2
log2^x=log4^x,则x=
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解log2^(x+1)=log4^(x+13)
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解方程log2(2x)*log4(x/4)=2
log4 (x+2) = log2 (2x-1)
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对数方程log2（x-1）=log4 x,如何化成log2（x-1)²?
已知log2^3=a则log4^9=