4x^2+12xy+9y^2=0(xy≠0),怎么算?那是4x^2怎么算,得多少?

已知x-y=4xy且xy≠0,求代数式-x-2xy+y分之2x+3xy-2y的值 已知2x²-3y²=xy,(xy≠0),求值（4xy-x²）／(xy+2y²)的值 已知x^2+4xy-12y^2=0,其中xy≠0,求x/y. 已知x^2+4xy-12y^2=0,其中xy≠0,求x/y.kuai 2x方-6xy+9y方-4x+4=0 xy=多少 （-3x^y+2xy)-( )=4x^+xy 已知2x-3根号xy-2y=0(x>0),求x^2+4xy-16y^2/x^2+xy-9y^2 已知X+Y=3,XY=-1,求2(X-Y)^4-9(X-Y)^2+12XY 5x的2次方-12xy 9y的2次方-4x 4=0,求xy的值已知：5x^2-12xy+9y^2-4x+4=0,求xy的值. 已知x-xy=8,xy-y=-9,求x+y-2xy的值 当x-y=2xy时,求4x-3xy-4y/xy 1-2/x+y=xy,4y+6x=xy.求xy的解? 解方程组,{x^2+2xy=0 ,y^2-4xy=9如上 x^2-7xy+12y^2=0,求x^2-2xy+y^2/2xy的值 已知x^2-xy=4,y^2-xy=9,求代数式x^2-2xy+y^2 已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=? 已知x²-7xy+12y²=0求x²-xy+y²/2xy的值 (x^2+2xy+y^2-4xy)*(x^2-2xy+y^2+4xy)