2^(log2^(-3))=如题

2^(log2^(-3))=如题 (log2 9)/(log2 8) = 2/3(log2 3) 2log2^3= log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 2log5(25)-3log2(64) 如题`怎么做? 若-3≤log1/2x≤-1/2,求f(x)=(log2 x/2）*(log2 x/4)的最大值和最小值如题 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 求解log2(3x)=log2(2x+1) (log2 6)×(log3 6)-(log2 3+log3 2)= (log2 6)×(log3 6)-(log2 3+log3 2)= 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ log2(3)*log3(2)=? (log3^2)(log2^3)= 解方程log2(x+14)-log2(x+6)=3-log2(x+2) 求log2 1-log2 0.105=3.25为什么是怎么算的?如题 log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙! =[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊 log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X