2lg 5+lg2*lg50=1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 08:13:36
2lg5+lg2*lg50=12lg5+lg2*lg50=12lg5+lg2*lg50=1=lg5*lg5+lg2(lg5+lg10)=lg5*lg5+lg2(lg5+1)=lg5*lg5+lg5*l
2lg 5+lg2*lg50=1
2
lg 5+lg2*lg50=1
2lg 5+lg2*lg50=1
=lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1
首先你要记得公式: a^[logc(b)]=b^[logc(a)]
这道题是这样的=lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1
lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1
=1
2lg 5+lg2*lg50=1
lg25+lg2*lg50+lg^2 2=?
lg50+lg2*lg5+lg²2=?
(lg^2)^2+lg^2*lg^50+lg^25=?(lg2)^2+lg2*lg50+lg25=?
计算:|lg2-lg^2(5)|+lg2·lg50+√(lg5-1)^2
lg25+lg2*lg50+(lg2)^2+1=?
lg的平方5+lg2 ×lg50
计算lg的平方5+lg2*lg50
lg25+lg2*lg50+lg平方2
1g^2+lg2*lg50=?
lg2.lg50=lg2.{lg(2.lg50怎么推出lg(2.25)的?
|lg2—lg平方5|+ lg2*lg50+ 根号(lg5-1)平方
求(lg50)^2+lg2*lg(50)^2+(lg2)^2
求值:lg25 lg2*lg50 (lg2)^2求值:1 lg25+lg2*lg50+(lg2)^2 2 已知集合 {x,y,lg(xy)}={0,y,绝对值x},求log8(x^2+y^2)的值
(lg5)^2+lg2×lg50=?
(lg5)^2 + (lg2)*(lg50)=
(lg5)^2+lg2*lg50=
lg25+lg2·lg50+(lg2)^2=?