化简sin^6a+cos^6+3sin^2acos^2a的结果是?
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化简sin^6a+cos^6+3sin^2acos^2a的结果是?化简sin^6a+cos^6+3sin^2acos^2a的结果是?化简sin^6a+cos^6+3sin^2acos^2a的结果是?s
化简sin^6a+cos^6+3sin^2acos^2a的结果是?
化简sin^6a+cos^6+3sin^2acos^2a的结果是?
化简sin^6a+cos^6+3sin^2acos^2a的结果是?
sin^6α+cos^6α+3sin^2αcos^2α
=(sin^2a)^3+(cos^2a)^3+3sin^2αcos^2α
=(sin^2a+cos^2a)(sin^4a-sin^2acos^2a+cos^4a)+3sin^2αcos^2α
=sin^4a-sin^2acos^2a+cos^4a+3sin^2αcos^2α
=sin^4a+2sin^2acos^2a+cos^4a
=(sin^2a+cos^2a)^2
=1
原式=(sin²a+cos²a)(sin^4a-sin²acos²a+cos^4a)+3sin²acos²a
=1×(sin^4a-sin²acos²a+cos^4a)+3sin²acos²a
=sin^4a-sin²acos²a+cos^4a+3sin²acos²a
=sin^4a+2sin²acos²a+cos^4a
=(sin²a+cos²a)²
=1²
=1
原式=(sin²a+cos²a)(sin^4a-sin²acos²a+cos^4a)+3sin²acos²a
=1×(sin^4a-sin²acos²a+cos^4a)+3sin²acos²a
=sin^4a-sin²acos²a+cos^4a+3sin²acos²a
=sin^4a+2sin²acos²a+cos^4a
=(sin²a+cos²a)²
=1²
=1
[Sin(6π+a)Cos(7π-a)]/[Sin(3π+a)+Sin(-π+a)
化简cos(π/3+a)+sin(π/6+a)
化简:cos(π/3+a)+sin(π/6)+a=
化简sin^6a+cos^6+3sin^2acos^2a的结果是?
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
sin^6 a+cos^6 a+3×sin^2 a×cos^2 a=?
化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)mingbaidian
2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
化简1-cos^4a-sin^4a/1-cos^6-sin^6acos^6应为cos^6a
已知(4sin a-2cos a)/(5cos a +3sin a)=6/11,求cos^4 a-sin^4 a
[sin(a-6π)cos(7π/2-a)]/[sin(3π+a)+sin(a-π)】=
sin^6 a+cos^6 a+3sin^2 acos^2a=(sin^2 a+cos^2 a)(sin^4 a+cos^4 a-sin^2 acos^2 a)是如何计算出的
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简sina^8-cosa^8-sin^6a+cos^6a+sin^4a
化简sinα^6+cosα^6+3sinα^2cosα^2的结果是