1/4x+(2200-x)*1/5=500怎样解?
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1/4x+(2200-x)*1/5=500怎样解?1/4x+(2200-x)*1/5=500怎样解?1/4x+(2200-x)*1/5=500怎样解?(1/4)x+(2200-x)*1/5=500两边
1/4x+(2200-x)*1/5=500怎样解?
1/4x+(2200-x)*1/5=500怎样解?
1/4x+(2200-x)*1/5=500怎样解?
(1/4)x+(2200-x)*1/5=500
两边乘以20得
5x+4(2200-x)=10000
5x+8800-4x=10000
x=1200
1/4x+(2200-x)*1/5=500
1/4x+440-1/5x=500
1/20x=60
x=1200
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=(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+25x^2+10x^2-50x+24 这是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24
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