当xx-1/2x^2
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当xx-1/2x^2当xx-1/2x^2当xx-1/2x^2(注,原题有误,应为<号)令f(x)=ln(1+x)-x+(1/2)x^2求得f''(x)=(x^2)/(1+x)显然,f(x)的定义域为(-
当xx-1/2x^2
当xx-1/2x^2
当xx-1/2x^2
(注,原题有误,应为<号)
令 f(x)=ln(1+x)-x+(1/2)x^2
求得
f'(x)=(x^2)/(1+x)
显然,f(x)的定义域为(-1,+无穷),即在其定义域内,有
f'(x)≥0
又
f(0)=0
而在区间(-1,0)
f'(x)>0
故必有
f(x)-f(0)<0
即
f(x)<f(0)=0
即
ln(1+x)-x+(1/2)x^2<0
即
ln(1+x)<x+(1/2)x^2
当xx-1/2x^2
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解方程1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20)=5/(xx+11x-708)
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