(5x-1)÷4=(3x+1)÷2-(2-x)÷3 求x的解.

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || [x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简 (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)2.2/3+x/(3x-1)=1/9x-3 (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 先化简,再求值：（1）（x+1/x²-x-x/x²-2x+1）÷1/x,x=根号2+1 （2）（1+x-3/x+3）÷2x/x²-9 x=根号3+3 （3）4-x/x-2÷（x+2-12/x-2）x=根号3-4 （4）x-3/2x-4÷（5/x-2-x-2） x=根号3-2 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 1.(x^3-x^2-4x+1)/(x^2-3x+2)-(x^3-2x^2-9x+21)/（x^2-5x+6）+（x^2-3x+8）/（x^2-4x+3）2.{(x^2)/（x-y)}*{y/(x+y)}-{(x^4y)/(x^4-y^4)}÷{（x^2/x^2+y^2）^2} 当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2) 先化简再求值 x²-2x/x÷(x-4/x) 其中x=3(1+1/x-2)÷x²-2x+1/x²-4 其中x=-5[1+2x-4/(x+1)(x-2)]÷x+3/x²-1 其中x=6 x^5-x^4+x^3-x^2+x-1 16-x^2/x^2-2x-3÷1^2-5x+4/x-3 【化简求值】(x分之x+2 - x-2分之x-1)÷x分之x-4【化简求值】(x分之x+2 - x-2分之x-1)÷x分之x-4x=3 X^2-3X-2=0,求( x - 2x-1/x )÷(x-1)/(x^2-2x) 先化简再求值：（x+2/x²-2x - x-1/x²-4x+4）÷ x-4/x,其中x=3/2