lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
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lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)lim(x趋向于0)(1+sinx-cosx
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
(1+sinx-cosx)/(1+sinβx-cosβx)
=(sinx+2(sin(x/2))^2)/(sinbx+2(sin(bx/2))^2)
=[(sin(x/2)+cos(x/2))/(sin(bx/2)+cos(bx/2))]*(sin(x/2)/sin(bx/2))
极限与下式的极限相等
(cos(x/2)/cos(bx/2))*(sin(x/2)/sin(bx/2))
=sinx/sinbx极限为1/b.
lim(x趋向于0)sinx/x=1,那么lim(x趋向于0)x/sinx=?怎么算?
lim(sinx/x)= 1 当x趋向于0时?当x趋向于0时 lim(sinx/x)= 1
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
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