(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值

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(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值(4x-2y-1)^2+√xy-2=0,

(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值
(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值

(4x-2y-1)^2+√xy-2=0,求4x^2y-4x^2y2+xy^2的值
由题意得4x-2y=1 xy=2 所以原式=xy(4x-4xy+y)=2(4x+y-8) 然后解得xy即可
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