lim(1/x)ln(1+x+x^2)(x→0)解答过程

lim[ln(1+x)+ln(1-x)]/(tanx)^2 计算：lim[1/x+1/(x^2)ln(1-x)] lim(x->0)ln(1+2x)/e^x-1 lim(x趋向0)ln(1+sin x)/x^2 lim(x趋于0)[ln(1+2x)]/x lim(x趋近于0)[1/ln(x+根号1+x^2)-1/ln(1+x)] 求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx 为什么 lim ln[(1+1/x)^x]=ln e lim(x→0)(cosx)^(1/ln(1+x^2)) lim ln(1+e^x)/根号(1+x^2) lim ln(1+e^x)/根号(1+x^2) lim(x→0)ln（x^2+1）等于 怎么计算lim(x->0+)x^(1/2)*ln(sinx)? lim x趋于0 ln (1+2x)/sin3x lim e^2x-1/ln(1-X) 0lim e^2x-1/ln(1-X) 0 的极限 lim ln(1+x)/x 怎么推到lim ln(1+x)1/x 求极限(1). lim(x-o) ln(sinx/x) (2). lim(n->∞){x[ln(x+a)-lnx]} lim((ln(1+x))/x)^(1/x) x->无穷大