求lim x→0 1-cos2x/x·sinx极限

求lim(1-cos2x)/x^2极限,x→0 求极限lim(x→0) tanx-sinx/1-cos2x lim(x→0)(1-cos2x)/xsinx 求lim x→0 1-cos2x/x·sinx极限 求lim(x→∞)1-cos2x/xsinx lim((x→0)(1-cos2x)/(x*sinx) 计算题 lim(x→0)【(√4-x^2-2)/(1-cos2x)】求极限 lim(x趋向0) 1-cos2x/xsinx 2.5计算极限lim(x→0) (1-cos2x)/xsinx 求极限:lim(x→0)(1/x^2)[1-cosx(cos2x)^(1/2)(cos3x)^(1/3) lim(x→0)(1-cos2x)/(x*sin2x) lim(x→0)(xcot2x) lim(x→无穷)(1+(1/2x))^x 求极限 lim(x→0){(cos2x-cos3x)/[(1+x^2)-1]}打错了。应该是lim(x→0)(cos2x-cos3x)/{[（1+x^2）^1/2]-1} 求教lim x→0 ( cos x / cos2x )^(1/x^2) 求lim(x→0)(cos2x)^x^1/2以及limx(x→∞)(lnx)^[1/(x-1)]要过程第一个用对数求极限法 lim x→0{1-cos(1-cos2x)}/sinx^4用等价无穷小量求此极限. lim x→0 ln(cos5x)/ln(cos2x)要过程 lim(x→0)(cos2x-cos3x)/{[（1+x^2）^1/2]-1} lim(x→0)(cos2x-cos3x)/{[（1+x^2）^1/2]-1}