求极限lim(x→0) tanx-sinx/1-cos2x
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求极限lim(x→0)tanx-sinx/1-cos2x求极限lim(x→0)tanx-sinx/1-cos2x求极限lim(x→0)tanx-sinx/1-cos2x原式=lim(sinx/cosx
求极限lim(x→0) tanx-sinx/1-cos2x
求极限lim(x→0) tanx-sinx/1-cos2x
求极限lim(x→0) tanx-sinx/1-cos2x
原式=lim(sinx/cosx-sinx)/(1+cosx)(1-cosx)
=limsinx(1-cosx)/[cosx(1+cosx)(1-cosx)]
=limsinx/[cosx(1+cosx)]
=0/1*2
=0
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