double四舍五入int i = 455;double d1;d1 = 455*0.001;sprintf(amt1,"%.2f",d1);printf("%s",amt1);打印为 0.46但如果d1 = 455*0.005(2.75); 打印的就为2.27(应该为2.28),为什么在这里没有进位

double fun(int i,double x,double double f(double x); {double a=0;int i; for (i=0;i #include double fun( int m ){double t = 1.0;int i;for( i = 2; i 怎么求值啊?#include double f(int n){int i;double s;s=1.0;for(i=1;i 以下函数用以求x的y次方 double fun(double x,int y){int i；double z=1.0；for（i=1；i C++ 矩阵加法#includeusing namespace std;void plus(double a[],double b[],int m,double c[]) {int i;for(i=0;i #includeusing namespace std;#define PI 314159double area(double radius=0);double area(double a,double b);double area(double a,double b,double h);double area(double a,double b,double c,int);int main(){cout C语言 一个定义函数 求详解.double fx（double）{return exp（x）；｝double intf（double （*f）（double）,double a,double b,int n）{double sum,h；int i；h=（b-a）/n;sum=(f(a)+f(b))/2.0;for (i=1;i n=(int)sqrt((double)i)中为什么要把i转变成double型?是不是math.h里的函数都要用double型?为什么呢? double四舍五入int i = 455;double d1;d1 = 455*0.001;sprintf(amt1,%.2f,d1);printf(%s,amt1);打印为 0.46但如果d1 = 455*0.005(2.75); 打印的就为2.27(应该为2.28),为什么在这里没有进位 编写程序 计算组合数的公式#include int main(void){double fact(int n,int m);int i,p,m,n;double result,product,case;printf(Enter n,m:);scanf(%d%d,&n,&m);for(i = 0;i 这个C++梯形法求定积分的函数为什么错了double tixing(double (*f)(double),double a,double b){int n=1000,i;double s,sum=0,d;d=(b-a)/n;double y1=(*f)(a+i*d);double y2=(*f)(a+i*d-d);for (i=1;i 这个c程序哪错了?求二元一次方程解的.#include#includevoid prin();double xone(double,double,double);double xtwo(double,double,double);int main(void){double a,b,c,i,value1,value2;print();scanf(%fx2+%fx+%f=%f,&a,&b,&c,&i);printf(you inp C语言中,double型转成int型是用的四舍五入还是直接取double型的整数部分? 高斯消去#includeusing namespace std;void gshh(double a[][4],int x); // 高斯换行void gsbh(double a[][4],int x); //高斯变换void gshd(double a[][4]); //高斯回代void gshh(double a[][4],int x){ // 高斯换行int t=x;for(int i=x;ia[i+1][x] 有关浮点数的运算程序A：double f(int x){ return 1.0 / x ; }void main(){ double a ,b;int i ;a = f(10) ;b = f(10) ;i = a == b ;printf( %d ,i ) ;}程序B：double f(int x){ return 1.0 / x ; }void main(){ double a ,b ,c;int i ;a = f(10) ;b 以下函数的功能是：求x的y次方,请填空.#include stdio.hdouble fun( double x, int y) { int i=1; double z; for(z=x; i 1-1/2+1/3-1/4+……+1/99-1/100求值,想问这里的double为啥不能换成float?int main(int argc, char *argv[]){ double s=0; int i; for(i=1;i