(2x+y)∧2-(x+2y)∧2
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(2x+y)∧2-(x+2y)∧2(2x+y)∧2-(x+2y)∧2(2x+y)∧2-(x+2y)∧2原式=(2x+y+x+2y)(2x+y-x-2y)=(3x+3y)(x-y)=3(x+y)(x-y
(2x+y)∧2-(x+2y)∧2
(2x+y)∧2-(x+2y)∧2
(2x+y)∧2-(x+2y)∧2
原式=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
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