关于杨辉三角形的问题化简：（x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)a^5+5a^4+10a^3+10a^2+5a+1=(a+1)^5(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)=(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)+1-1=(x-1+1)^5-1=x^5-1为什么【a^5+5a^4+10a
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关于杨辉三角形的问题化简：（x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)a^5+5a^4+10a^3+10a^2+5a+1=(a+1)^5(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)=(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)+1-1=(x-1+1)^5-1=x^5-1为什么【a^5+5a^4+10a
关于杨辉三角形的问题
化简：（x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)
a^5+5a^4+10a^3+10a^2+5a+1=(a+1)^5
(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)=
(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)+1-1=
(x-1+1)^5-1
=x^5-1
为什么【a^5+5a^4+10a^3+10a^2+5a+1】等于【(a+1)^5】
其他的都懂了
关于杨辉三角形的问题化简：（x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)a^5+5a^4+10a^3+10a^2+5a+1=(a+1)^5(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)=(x-1)^5+5(x-1)^4+10(x-1)^3+10(x-1)^2+5(x-1)+1-1=(x-1+1)^5-1=x^5-1为什么【a^5+5a^4+10a
杨辉三角
a^0=1
(a+1)^1=a+1
(a+1)^2=a^2+2a+1
(a+1)^3=a^3+3a^2+3a(^1)+1
(a+1)^4=a^4+4a^3+6a^3+4a^2+a+1
……
以此类推
1
1 1
1 2. 1
1. 3. 3. 1
1. 4. 6. 4. 1
1. 5. 10. 10. 5. 1
a[i][j]=a[i-1][j-1]+a[i-1][j]
a[i][j]是由上一行的两个数加起来得到的，所以是i-1行，而不是列，你都明白i是行j是列。。