1/(x^1/4+x^1/2)dx=

1/(x+x^2)dx ∫（x^2+1/x^4)dx ∫1/(x^4-x^2)dx ∫ x/(1+X^2)dx= ∫(x+1/x)^2dx=? ∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 不定积分 [1/(e^x+e^(-x))]dx=?根号{[(x^2)-1]/x}dx=? ∫(1+x)/(X^2)dx=∫ [(1+x)/(X^2)]dx得什么? 1/(x^1/4+x^1/2)dx= ∫(1-x)/[√(9-4x^2)]dx= ∫1/(x^2-5x+4)dx= 过程 求不定积分 ∫ [(x^4)/(1+x^2)]dx= ∫(x^3-x^2+x+1)/(x^2+1) dx∫(x+4)/(x^2-x-2) dx 1.dx/dt = 4-2x;2.dx/dt = 1+x. ∫x-根号下x dx ∫lx-2l dx ∫1/根号下（4-x^2) dx ∫e^(-x) dx ∫2/根号下x dx ∫(1/x^2)sin(1/x) dx 求不定积分 1/(1+cosx)dx ((xcosx+sinx)/(xsinx)^2)dx (x^2+1/(x^3+3x+1)^5 )dx 4arctanx-x/(1+x^2)dx ∫(x+2)/(4x-x^2)^1/2dx