x+2z=3 2x+y=2 2y+z=7怎么解?
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x+2z=32x+y=22y+z=7怎么解?x+2z=32x+y=22y+z=7怎么解?x+2z=32x+y=22y+z=7怎么解?x+2z=312x+y=222y+z=73由一得:X=3-2Z4将4
x+2z=3 2x+y=2 2y+z=7怎么解?
x+2z=3 2x+y=2 2y+z=7怎么解?
x+2z=3 2x+y=2 2y+z=7怎么解?
x+2z=3 1
2x+y=2 2
2y+z=7 3
由一得:
X=3-2Z 4
将4代入2得
2(3-2Z)+Y=2 5
于是5和3组成一个2元一次方程组
2(3-2Z)+Y=2 5
2y+z=7 3
由5*2-3得:
12-9Z=-3
- 9Z=-15
Z=5/3
将Z=5/3代入4得:
X=-1/3
将X=-1/3代入2得:
Y=8/3
所以X=-1/3,Y=8/3,Z=5/3
x=-1/3
y=8/3
z=5/3
x+2z=3--------1)
2x+y=2--------2)
2y+z=7--------3)
2)-1)×2,得
y-4z=-4--------4)
3)-4)×2,得
9z=15,z=5/3
y=8/3
x=-1/3
oh 来晚了
x+2z=3
2x+y=2
2(x+2z)-2x-y=6-2
4z-y=4
2y+z=7
2(4z-y)+2y+z=15
9z=15 z=5/3
2y+5/3=7
y=8/3
x+10/3=3
x=-1/3
所以 x=-1/3 y=8/3 z=5/3
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