2x+y+z=4 x+2y+z=12 x+y+2z=24
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2x+y+z=4x+2y+z=12x+y+2z=242x+y+z=4x+2y+z=12x+y+2z=242x+y+z=4x+2y+z=12x+y+2z=242x+y+z=4x+2y+z=12x+y+2
2x+y+z=4 x+2y+z=12 x+y+2z=24
2x+y+z=4 x+2y+z=12 x+y+2z=24
2x+y+z=4 x+2y+z=12 x+y+2z=24
2x+y+z=4
x+2y+z=12
x+y+2z=24
三式相加得4x+4y+4z=40
得x+y+z=10
用三个原方程分别减去此式得:
x=4-10=-6
y=12-10=2
z=24-10=14
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