解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
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解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)解不等式log(1/2)(x^2+2x-3)>log
解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
由于 1/2
log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
x^2+2x-3<3x+1
x^2-x-4<0
(x-1/2)^2<17/4
1/2-二分之根17
log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
(x^2+2x-3)<(3x+1)
x^2-x-4<0, x^2-x-4=0
x=(1±√17)/2 , (1-√17)/2
3x+1>0 ,x>-1/3
1
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