x^2-y^2-2y-1

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x^2-y^2-2y-1x^2-y^2-2y-1x^2-y^2-2y-1x^2-y^2-2y-1=x²-(y²+2y+1)=x²-(y+1)²=(x-y-1)(

x^2-y^2-2y-1
x^2-y^2-2y-1

x^2-y^2-2y-1
x^2-y^2-2y-1
=x²-(y²+2y+1)
=x²-(y+1)²
=(x-y-1)(x+y+1)

x^2-y^2-2y-1
=x²-(y²+2y+1)
=x²-(y+1)²
=(x+y+1)(x-y-1)

是化简么?

那是要求y还是x啊

x"2-(y+1)"2
(x-y-1) (x+y+1)

因式分解?
原式=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x+y+1)(x-y-1)