x^2-y^2-2y-1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 16:50:10
x^2-y^2-2y-1x^2-y^2-2y-1x^2-y^2-2y-1x^2-y^2-2y-1=x²-(y²+2y+1)=x²-(y+1)²=(x-y-1)(
x^2-y^2-2y-1
x^2-y^2-2y-1
x^2-y^2-2y-1
x^2-y^2-2y-1
=x²-(y²+2y+1)
=x²-(y+1)²
=(x-y-1)(x+y+1)
x^2-y^2-2y-1
=x²-(y²+2y+1)
=x²-(y+1)²
=(x+y+1)(x-y-1)
是化简么?
那是要求y还是x啊
x"2-(y+1)"2
(x-y-1) (x+y+1)
因式分解?
原式=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x+y+1)(x-y-1)
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
化简y(x+y)+(x+y)(x-y)-x^2
(x-y)(2x-y-1)
[(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
(x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
[(x-y)^2-(x+2y)(x-2y)]/y
求(1+y)-2x(1+y)+x(1-y)
把4(x-y+1)+y(y-2x)因式分解
y(y+2)+4x(x-y-1)因式分解是多少
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简
(x-y/1-x+y/1)÷2y/y-x计算错了,是(1/x-y-1/x+y)÷2y/y-x
计算:y-x分之x+y+x-y分之y-y-x分之2x-y