已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an
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已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an已知数列满足a1=1,根号a(n-1)-
已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an
已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an
已知数列满足a1=1,根号a(n-1)-根号an=根号an*a(n-1),求an
等式两边同时除以根号下an×a(n-1)
得 1/√an-1/√a(n-1)=1
令bn=1/√an
则bn-b(n-1)=1 {bn}为公差是1 首项是1的等差数列
求得bn=n
进一步得an=1/n²
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