3x^5+5x^3-30x+4=0 有多少个实根?证明你的答案

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, 5(x的2次方+X-3)-4x(6+x)+x(-x+4)=0 x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 计算：(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程 用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+. (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x-2x+3x-4x+5x.+99x-100x=25求解 2x+3x+4x+5x+x+6x+7x=100 x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x 设f(x)=x^5+2x^4+3x^3+4x²+5x+6,证明f(x)=0至少有一实根 若x^3+x^2+x+1=0,求代数式1+x+x^2+x^3+x^4+x^5+...+x^2006+x^2007的值 设f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f’(x)=0在[2,5]内有实根个数为 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? 4x²+5x=81 x(x+5)=0 (2x-x)(x-1)=0 x(x+5)=5x-10 (3x-2)(x+1)=x(2x-1) 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 数学f(x)=x(x+1)(x+2)(x+3)(x+4)(x+5),求f'(0)=? 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7