若数列an满足an=4n-1 又有数列bn满足bk=1/k（a1+a2+……+ak）求数列{bn}得前n项和Sn

若数列an满足an=4n-1 又有数列bn满足bk=1/k（a1+a2+……+ak）求数列{bn}得前n项和Sn 若数列{an}满足条件log2(1+an)=n,求数列{an}通项公式an= 数列an满足,a1=1/4,a2=3/4,an+1=2an-an-1(n≥2,n属于N*),数列bn满足b1 若数列【an】满足a1等于1,An+1=2an+3n,则数列的项A5 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 已知数列{an}满足an+1+an=4n-3(n∈N*),若对任意n∈N*,都有an^2+an+1^2>=20n-15成立,则a1的取值范围是 设数列{an}满足an=2an-1+n 若{an}是等差数列,求{an}通项公式 设b＞0,数列an满足a1=b,an=nban-1/an-1+n-1（n≥2）求数列an通向公式. 设b＞0,数列an满足a1=b,an=nban-1/an-1+n-1（n≥2）求数列an通向公式 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5,求数列{an}的通项公式 【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通...【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通项公式 若数列{an}满足a1>0,且a(n+1)=(n/n+1)乘以an,则数列{an}是 递增数列,递减数列 常数列 摆动数列求详解 已知数列{an}满足a1=b,an=nban-1/an-1+n-1(n大于等于2）,求数列an的通项公式 已知数列an满足a1=4,an=n+1/n-1乘以an-1则an= 已知数列｛an｝满足a1=4/3,且an+1=4（n+1）an/3an+n 如果数列{an}满足a1=4,an+1=an^2/2an-2,求当n>=2时,恒有an 已知数列﹛an﹜的前n项和为Sn,且Sn=4an-3（n∈N）证明：数列﹛an﹜是等比数列若数列﹛bn﹜满足b（n+1）=an+bn（n∈N﹚,且b1=2,求数列﹛bn﹜的通项公式