一道SAT数学题,at a certain hospital,89 children were born in the month of June.If more children were born on the fifteenth of June than on any other day in June.What is the least number of children that could have been born on the fifteenth of J
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一道SAT数学题,at a certain hospital,89 children were born in the month of June.If more children were born on the fifteenth of June than on any other day in June.What is the least number of children that could have been born on the fifteenth of J
一道SAT数学题,
at a certain hospital,89 children were born in the month of June.If more children were born on the fifteenth of June than on any other day in June.What is the least number of children that could have been born on the fifteenth of June.
我的答案是45,标准答案说是4,是我理解错了还是答案错了?
题目中有说明每天都有孩子出生吗？
一道SAT数学题,at a certain hospital,89 children were born in the month of June.If more children were born on the fifteenth of June than on any other day in June.What is the least number of children that could have been born on the fifteenth of J
他不是问你15号那天最少要生多少个才能一定比其他每一天生的都多.而是15号生的baby最少的是多少就可以满足比其它每一天都多.这是一种可能性.所以就是这天最少要生4个.剩下的每一天生3个,有一天生1个.只有这种情况下15号生的baby比其它每天都多 而且也达到最小值
你好，参考答案是对的，自己再理解一遍吧！不仅英文要看懂，还要会分析题目本身。
答案完全正确，注意the least number ！最少的，如果是3，则2*（30-1）=58，总数达不到89，而如果是4，则3*29=87，总数可以满足条件
首先你得看懂题目 比其他月都大的最小值
第一种方法：仅仅从题目认知角度 89/30=2.9667 所以最小值大于等于3
此时带3进去
86/29=2.95 介于2和3之间 就一定有大于等于3的
此时就不满足more than any other
此时带4进去
85/29=2.93 介于2和3之间 有可能剩下的数就只有3 2 1了
所以答案...
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首先你得看懂题目 比其他月都大的最小值
第一种方法：仅仅从题目认知角度 89/30=2.9667 所以最小值大于等于3
此时带3进去
86/29=2.95 介于2和3之间 就一定有大于等于3的
此时就不满足more than any other
此时带4进去
85/29=2.93 介于2和3之间 有可能剩下的数就只有3 2 1了
所以答案是4
第二种方法：设人数最多的一天有X人出生，要他的值最小 就是让其他29天出生人数最大 也就是X-1 这样列方程
X+29(X-1)＞＝89 解得X＞＝3.9333
取最小值4
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答案正确。注意要求15号出生人数在比其他日子都多的情况下的最小值，那么就需让其他29天出生人数尽可能相等并且最大。假设除了15号每天生4个，29天共生116个，超出89，所以每天最多只能生3个，15号生4个。而要是15号生3个，又不够89了，所以最少也得生4个。...
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答案正确。注意要求15号出生人数在比其他日子都多的情况下的最小值，那么就需让其他29天出生人数尽可能相等并且最大。假设除了15号每天生4个，29天共生116个，超出89，所以每天最多只能生3个，15号生4个。而要是15号生3个，又不够89了，所以最少也得生4个。
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