sin(π/16)^2-cos(π/16)^2
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sin(π/16)^2-cos(π/16)^2sin(π/16)^2-cos(π/16)^2sin(π/16)^2-cos(π/16)^2sin(π/16)^2-cos(π/16)^2=-cosπ/8
sin(π/16)^2-cos(π/16)^2
sin(π/16)^2-cos(π/16)^2
sin(π/16)^2-cos(π/16)^2
sin(π/16)^2-cos(π/16)^2
=-cosπ/8
=-√[(1+cosπ/4)/2]
=-√[(1+√2/2)/2]
=-√(2+√2)*1/2
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16
sin(π/16)^2-cos(π/16)^2
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