tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,

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tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,tanθ=a,求[sin(pi/4+θ)

tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,
tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,

tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,
[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ
=[sin(pi/4+θ)/cosθ]*tan2θ
=[(sinπ/4cosθ+cosπ/4sinθ)/cosθ]*tan2θ
=[√2/2×(cosθ+sinθ)/cosθ]*tan2θ
=[√2/2×(1+tanθ)]*tan2θ
=√2/2×(1+tanθ)*tan2θ
=√2/2×(1+tanθ)*2tanθ/(1-tan²θ)
=√2×tanθ/(1-tanθ)
=√2a/(1-a)

tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ, tana=2求sin(pi-a)cos(2pi-a)sin(-a+3pi/2)/tan(-a-pi)sin(-pi-a) f(a)=sin(pi-a)cos(2pi-a)tan(-a+3pi/2)/cos(-pi-a) 求 f(-31pi/3)的值 sin(pi/4+2a)sin(pi/3-2a)=1/4,a属于(pi/4,pi/2),求2sin^2a+tana-cota-1 cosa=2/3 a是第四象限角求sin(a-2Pi)+sin(-a-3Pi)cos(a-3Pi)/cos(Pi-a)-cos(-Pi-a)cos(a-4Pi) 【急在线等】sina0,f(a)=[sin(pi-a)*cos(2pi-a)*tan(-a)]/[tan(11pi-a)*sin(13pi+a)].(1).如果cos(a-3pi/2)=1/5,求f(a).(2).求f(-1860° ). 1,已知sin(a-pi/3)=1/3,则cos(pi/6+a)= 2,cos29pi/6= 3,cos(pi+a)=-1/3,则(sin2pi/3-a)= 急4,sin(2pi+a)/cos(pi+a)=-3,求(2cos(pi-a)-3sin(pi+a))/(4cos(-a)+sin(2pi-a))的值尽量过程 化简间sin(a-2pi)cos(a+pi)tan(a-99pi)cos(pi-a)sin(3pi-a)sin(-a-pi) cos(pi/4-a)=3/5 sin(3pi/4+b)=5/13 求sin(a+b) 已知f(a)=2tan a-(2sin^2a/2-1)/(sin a/2cos a/2),求f(pi/2) 第一题 cos(a+b)=4/5.cos(a-b)= -4/5 .a+b∈[7pi/4,2pi].a-b∈[3pi/4,pi].cos2a=?第二题 证明 tan(第二题 证明 tan(θ+π/4) = [tanθ+1]/[1- tanθ] 已知tanθ=a(a>1),求sin(π/4+θ)/sin(π/2-θ)×tan2θ的值 matlab求解方程.f=x*sin(y)+((pi*12/4+(60-x)*tan(pi/9))+48*y)*tan(pi/9)=0,其中x范围为30到60,求y. MATLAB编程 求大侠改错a=-pi:pi/50:pi;b=pi:pi/50:4*pi;x=1:0.1:8;subplot(1,3,1),plot(a,a.*cos(a))xlabel('x'),ylabel('y'),title('y=xcosx')subplot(1,3,2),plot(b,b.*tan(1/b).*sin(b.^3))gtext('y=xtanxsinx '),axis([3 13 0 100])subplot(1,3,3),plot(x,ex tana=0.5求tan(pi/2+2a) 化简(高一)[sin^2(pi+a)cos(pi+a)]/[tan(pi+a)cos^3(-pi-a)tan(2pi+a)] 已知sina,cosa是关于的方程x^2-bx+b=0(a)的两个根.(1)求cos^3(pi/2-a)+sin^(pi/2-a)的值()求tan(...已知sina,cosa是关于的方程x^2-bx+b=0(a)的两个根.(1)求cos^3(pi/2-a)+sin^(pi/2-a)的值()求tan(pi-a)-1/tana的值