已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a

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已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a已知sin(a+B)sin(a-B)=1/3,求cos2b-

已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a

已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
cos2b-cos2a
=cos[(a+b)-(a-b)]-cos[(a+b)+(a-b)]
=[cos(a+b)cos(a-b)+sin(a+b)sin(a-b)]-
[cos(a+b)cos(a-b)-sin(a+b)sin(a-b)]
=2sin(a+b)sin(a-b)
=2/3