求极限:lim(1-x)tan Π/2

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求极限:lim(1-x)tanΠ/2求极限:lim(1-x)tanΠ/2求极限:lim(1-x)tanΠ/2tan(πx/2)吧?lim(x→1)(1-x)tan(πx/2)=lim(x→1)(1-x

求极限:lim(1-x)tan Π/2
求极限:lim(1-x)tan Π/2

求极限:lim(1-x)tan Π/2
tan(πx/2)吧? lim(x→1) (1-x)tan(πx/2)=lim(x→1) (1-x) sin(πx/2)/cos(πx/2)=lim(x→1) (1-x) /cos(πx/2)=lim(x→1) (1-x) /sin(π/2-πx/2)=lim(x→1) (1-x) /(π/2-πx/2)=2/π
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