直线L过原点,且点(3,5)到直线l的距离等於2,求L直线的方程
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/28 01:27:12
直线L过原点,且点(3,5)到直线l的距离等於2,求L直线的方程
直线L过原点,且点(3,5)到直线l的距离等於2,求L直线的方程
直线L过原点,且点(3,5)到直线l的距离等於2,求L直线的方程
因为直线L过原点,设方程为:
y=kx,即:kx-y=0
因为点(3,5)到直线的距离是:2
所以:
|3k-5|/根号(k^2+1)=2
(3k-5)^2=4(k^2+1)
9k^2-30k+25=4k^2+4
5k^2-30k+21=0
k=3+/-2根号(30)/5
所以所求的方程是:
y=[3+/-2根号(30)/5]*x
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